3.82 \(\int \frac {x^2}{(a+b \log (c x^n))^3} \, dx\)

Optimal. Leaf size=105 \[ \frac {9 x^3 e^{-\frac {3 a}{b n}} \left (c x^n\right )^{-3/n} \text {Ei}\left (\frac {3 \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{2 b^3 n^3}-\frac {3 x^3}{2 b^2 n^2 \left (a+b \log \left (c x^n\right )\right )}-\frac {x^3}{2 b n \left (a+b \log \left (c x^n\right )\right )^2} \]

[Out]

9/2*x^3*Ei(3*(a+b*ln(c*x^n))/b/n)/b^3/exp(3*a/b/n)/n^3/((c*x^n)^(3/n))-1/2*x^3/b/n/(a+b*ln(c*x^n))^2-3/2*x^3/b
^2/n^2/(a+b*ln(c*x^n))

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Rubi [A]  time = 0.11, antiderivative size = 105, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.188, Rules used = {2306, 2310, 2178} \[ \frac {9 x^3 e^{-\frac {3 a}{b n}} \left (c x^n\right )^{-3/n} \text {Ei}\left (\frac {3 \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{2 b^3 n^3}-\frac {3 x^3}{2 b^2 n^2 \left (a+b \log \left (c x^n\right )\right )}-\frac {x^3}{2 b n \left (a+b \log \left (c x^n\right )\right )^2} \]

Antiderivative was successfully verified.

[In]

Int[x^2/(a + b*Log[c*x^n])^3,x]

[Out]

(9*x^3*ExpIntegralEi[(3*(a + b*Log[c*x^n]))/(b*n)])/(2*b^3*E^((3*a)/(b*n))*n^3*(c*x^n)^(3/n)) - x^3/(2*b*n*(a
+ b*Log[c*x^n])^2) - (3*x^3)/(2*b^2*n^2*(a + b*Log[c*x^n]))

Rule 2178

Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[(F^(g*(e - (c*f)/d))*ExpIntegral
Ei[(f*g*(c + d*x)*Log[F])/d])/d, x] /; FreeQ[{F, c, d, e, f, g}, x] &&  !$UseGamma === True

Rule 2306

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_)*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[((d*x)^(m + 1)*(a + b*Log
[c*x^n])^(p + 1))/(b*d*n*(p + 1)), x] - Dist[(m + 1)/(b*n*(p + 1)), Int[(d*x)^m*(a + b*Log[c*x^n])^(p + 1), x]
, x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[m, -1] && LtQ[p, -1]

Rule 2310

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_)*((d_.)*(x_))^(m_.), x_Symbol] :> Dist[(d*x)^(m + 1)/(d*n*(c*x^n
)^((m + 1)/n)), Subst[Int[E^(((m + 1)*x)/n)*(a + b*x)^p, x], x, Log[c*x^n]], x] /; FreeQ[{a, b, c, d, m, n, p}
, x]

Rubi steps

\begin {align*} \int \frac {x^2}{\left (a+b \log \left (c x^n\right )\right )^3} \, dx &=-\frac {x^3}{2 b n \left (a+b \log \left (c x^n\right )\right )^2}+\frac {3 \int \frac {x^2}{\left (a+b \log \left (c x^n\right )\right )^2} \, dx}{2 b n}\\ &=-\frac {x^3}{2 b n \left (a+b \log \left (c x^n\right )\right )^2}-\frac {3 x^3}{2 b^2 n^2 \left (a+b \log \left (c x^n\right )\right )}+\frac {9 \int \frac {x^2}{a+b \log \left (c x^n\right )} \, dx}{2 b^2 n^2}\\ &=-\frac {x^3}{2 b n \left (a+b \log \left (c x^n\right )\right )^2}-\frac {3 x^3}{2 b^2 n^2 \left (a+b \log \left (c x^n\right )\right )}+\frac {\left (9 x^3 \left (c x^n\right )^{-3/n}\right ) \operatorname {Subst}\left (\int \frac {e^{\frac {3 x}{n}}}{a+b x} \, dx,x,\log \left (c x^n\right )\right )}{2 b^2 n^3}\\ &=\frac {9 e^{-\frac {3 a}{b n}} x^3 \left (c x^n\right )^{-3/n} \text {Ei}\left (\frac {3 \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{2 b^3 n^3}-\frac {x^3}{2 b n \left (a+b \log \left (c x^n\right )\right )^2}-\frac {3 x^3}{2 b^2 n^2 \left (a+b \log \left (c x^n\right )\right )}\\ \end {align*}

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Mathematica [A]  time = 0.13, size = 89, normalized size = 0.85 \[ \frac {x^3 \left (9 e^{-\frac {3 a}{b n}} \left (c x^n\right )^{-3/n} \text {Ei}\left (\frac {3 \left (a+b \log \left (c x^n\right )\right )}{b n}\right )-\frac {b n \left (3 a+3 b \log \left (c x^n\right )+b n\right )}{\left (a+b \log \left (c x^n\right )\right )^2}\right )}{2 b^3 n^3} \]

Antiderivative was successfully verified.

[In]

Integrate[x^2/(a + b*Log[c*x^n])^3,x]

[Out]

(x^3*((9*ExpIntegralEi[(3*(a + b*Log[c*x^n]))/(b*n)])/(E^((3*a)/(b*n))*(c*x^n)^(3/n)) - (b*n*(3*a + b*n + 3*b*
Log[c*x^n]))/(a + b*Log[c*x^n])^2))/(2*b^3*n^3)

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fricas [B]  time = 0.44, size = 211, normalized size = 2.01 \[ -\frac {{\left ({\left (3 \, b^{2} n^{2} x^{3} \log \relax (x) + 3 \, b^{2} n x^{3} \log \relax (c) + {\left (b^{2} n^{2} + 3 \, a b n\right )} x^{3}\right )} e^{\left (\frac {3 \, {\left (b \log \relax (c) + a\right )}}{b n}\right )} - 9 \, {\left (b^{2} n^{2} \log \relax (x)^{2} + b^{2} \log \relax (c)^{2} + 2 \, a b \log \relax (c) + a^{2} + 2 \, {\left (b^{2} n \log \relax (c) + a b n\right )} \log \relax (x)\right )} \operatorname {log\_integral}\left (x^{3} e^{\left (\frac {3 \, {\left (b \log \relax (c) + a\right )}}{b n}\right )}\right )\right )} e^{\left (-\frac {3 \, {\left (b \log \relax (c) + a\right )}}{b n}\right )}}{2 \, {\left (b^{5} n^{5} \log \relax (x)^{2} + b^{5} n^{3} \log \relax (c)^{2} + 2 \, a b^{4} n^{3} \log \relax (c) + a^{2} b^{3} n^{3} + 2 \, {\left (b^{5} n^{4} \log \relax (c) + a b^{4} n^{4}\right )} \log \relax (x)\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(a+b*log(c*x^n))^3,x, algorithm="fricas")

[Out]

-1/2*((3*b^2*n^2*x^3*log(x) + 3*b^2*n*x^3*log(c) + (b^2*n^2 + 3*a*b*n)*x^3)*e^(3*(b*log(c) + a)/(b*n)) - 9*(b^
2*n^2*log(x)^2 + b^2*log(c)^2 + 2*a*b*log(c) + a^2 + 2*(b^2*n*log(c) + a*b*n)*log(x))*log_integral(x^3*e^(3*(b
*log(c) + a)/(b*n))))*e^(-3*(b*log(c) + a)/(b*n))/(b^5*n^5*log(x)^2 + b^5*n^3*log(c)^2 + 2*a*b^4*n^3*log(c) +
a^2*b^3*n^3 + 2*(b^5*n^4*log(c) + a*b^4*n^4)*log(x))

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giac [B]  time = 0.56, size = 1029, normalized size = 9.80 \[ \text {result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(a+b*log(c*x^n))^3,x, algorithm="giac")

[Out]

-3/2*b^2*n^2*x^3*log(x)/(b^5*n^5*log(x)^2 + 2*b^5*n^4*log(c)*log(x) + b^5*n^3*log(c)^2 + 2*a*b^4*n^4*log(x) +
2*a*b^4*n^3*log(c) + a^2*b^3*n^3) - 1/2*b^2*n^2*x^3/(b^5*n^5*log(x)^2 + 2*b^5*n^4*log(c)*log(x) + b^5*n^3*log(
c)^2 + 2*a*b^4*n^4*log(x) + 2*a*b^4*n^3*log(c) + a^2*b^3*n^3) - 3/2*b^2*n*x^3*log(c)/(b^5*n^5*log(x)^2 + 2*b^5
*n^4*log(c)*log(x) + b^5*n^3*log(c)^2 + 2*a*b^4*n^4*log(x) + 2*a*b^4*n^3*log(c) + a^2*b^3*n^3) + 9/2*b^2*n^2*E
i(3*log(c)/n + 3*a/(b*n) + 3*log(x))*e^(-3*a/(b*n))*log(x)^2/((b^5*n^5*log(x)^2 + 2*b^5*n^4*log(c)*log(x) + b^
5*n^3*log(c)^2 + 2*a*b^4*n^4*log(x) + 2*a*b^4*n^3*log(c) + a^2*b^3*n^3)*c^(3/n)) - 3/2*a*b*n*x^3/(b^5*n^5*log(
x)^2 + 2*b^5*n^4*log(c)*log(x) + b^5*n^3*log(c)^2 + 2*a*b^4*n^4*log(x) + 2*a*b^4*n^3*log(c) + a^2*b^3*n^3) + 9
*b^2*n*Ei(3*log(c)/n + 3*a/(b*n) + 3*log(x))*e^(-3*a/(b*n))*log(c)*log(x)/((b^5*n^5*log(x)^2 + 2*b^5*n^4*log(c
)*log(x) + b^5*n^3*log(c)^2 + 2*a*b^4*n^4*log(x) + 2*a*b^4*n^3*log(c) + a^2*b^3*n^3)*c^(3/n)) + 9/2*b^2*Ei(3*l
og(c)/n + 3*a/(b*n) + 3*log(x))*e^(-3*a/(b*n))*log(c)^2/((b^5*n^5*log(x)^2 + 2*b^5*n^4*log(c)*log(x) + b^5*n^3
*log(c)^2 + 2*a*b^4*n^4*log(x) + 2*a*b^4*n^3*log(c) + a^2*b^3*n^3)*c^(3/n)) + 9*a*b*n*Ei(3*log(c)/n + 3*a/(b*n
) + 3*log(x))*e^(-3*a/(b*n))*log(x)/((b^5*n^5*log(x)^2 + 2*b^5*n^4*log(c)*log(x) + b^5*n^3*log(c)^2 + 2*a*b^4*
n^4*log(x) + 2*a*b^4*n^3*log(c) + a^2*b^3*n^3)*c^(3/n)) + 9*a*b*Ei(3*log(c)/n + 3*a/(b*n) + 3*log(x))*e^(-3*a/
(b*n))*log(c)/((b^5*n^5*log(x)^2 + 2*b^5*n^4*log(c)*log(x) + b^5*n^3*log(c)^2 + 2*a*b^4*n^4*log(x) + 2*a*b^4*n
^3*log(c) + a^2*b^3*n^3)*c^(3/n)) + 9/2*a^2*Ei(3*log(c)/n + 3*a/(b*n) + 3*log(x))*e^(-3*a/(b*n))/((b^5*n^5*log
(x)^2 + 2*b^5*n^4*log(c)*log(x) + b^5*n^3*log(c)^2 + 2*a*b^4*n^4*log(x) + 2*a*b^4*n^3*log(c) + a^2*b^3*n^3)*c^
(3/n))

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maple [F]  time = 0.93, size = 0, normalized size = 0.00 \[ \int \frac {x^{2}}{\left (b \ln \left (c \,x^{n}\right )+a \right )^{3}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2/(b*ln(c*x^n)+a)^3,x)

[Out]

int(x^2/(b*ln(c*x^n)+a)^3,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {3 \, b x^{3} \log \left (x^{n}\right ) + {\left (b {\left (n + 3 \, \log \relax (c)\right )} + 3 \, a\right )} x^{3}}{2 \, {\left (b^{4} n^{2} \log \relax (c)^{2} + b^{4} n^{2} \log \left (x^{n}\right )^{2} + 2 \, a b^{3} n^{2} \log \relax (c) + a^{2} b^{2} n^{2} + 2 \, {\left (b^{4} n^{2} \log \relax (c) + a b^{3} n^{2}\right )} \log \left (x^{n}\right )\right )}} + 9 \, \int \frac {x^{2}}{2 \, {\left (b^{3} n^{2} \log \relax (c) + b^{3} n^{2} \log \left (x^{n}\right ) + a b^{2} n^{2}\right )}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(a+b*log(c*x^n))^3,x, algorithm="maxima")

[Out]

-1/2*(3*b*x^3*log(x^n) + (b*(n + 3*log(c)) + 3*a)*x^3)/(b^4*n^2*log(c)^2 + b^4*n^2*log(x^n)^2 + 2*a*b^3*n^2*lo
g(c) + a^2*b^2*n^2 + 2*(b^4*n^2*log(c) + a*b^3*n^2)*log(x^n)) + 9*integrate(1/2*x^2/(b^3*n^2*log(c) + b^3*n^2*
log(x^n) + a*b^2*n^2), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {x^2}{{\left (a+b\,\ln \left (c\,x^n\right )\right )}^3} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2/(a + b*log(c*x^n))^3,x)

[Out]

int(x^2/(a + b*log(c*x^n))^3, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{2}}{\left (a + b \log {\left (c x^{n} \right )}\right )^{3}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2/(a+b*ln(c*x**n))**3,x)

[Out]

Integral(x**2/(a + b*log(c*x**n))**3, x)

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